|Chapter 8: Nucleophilic Substitution|
SN2 indicates a substitution, nucleophilic,
bimolecular reaction, described by the expression rate = k
This implies that the rate determining step involves an interaction between two species, the nucleophile and the organic substrate.
This pathway is a concerted process (single step) as shown by the following reaction coordinate diagrams, where there is simultaneous attack of the nucleophile and displacement of the leaving group.
|The nucleophile attacks at the carbon with the partial positive charge as a result of the polar s bond to the electronegative atoms in the leaving group.|
|Single step reactions have no intermediates and a
single transition state (TS).
In an SN2 there is simultaneous formation of the carbon-nucleophile bond and breaking of the carbon-leaving group bond, hence the reaction proceeds via a TS in which the central C is partially bonded to five groups.
|General case||SN2 reaction|
Let's look at how the various components of the reaction influence the reaction pathway:
Reactivity order : CH3- > CH3CH2- > (CH3)2CH- > (CH3)3C-
|In an SN2 reaction, the transition state has 5 groups around the central C atom. As a consequence of the steric requirements at this center, less highly substituted systems (i.e. more smaller H groups) will favour an SN2 reaction by making it easier to achieve the transition state.|
The following two series of JSMOL images show four alkyl
bromides and the iodide ion as the nucleophile with relative rate of reaction
Use the lower row of space filling models (which are great for seeing steric effects) to rotate the molecules to look at the electrophilic C center from the side opposite to the leaving group (which is where the nucleophile attacks from) to see how much of the electrophilic center you can see. In order to do this, you need to rotate the model so that the Br atom (maroon) is as much out of site as possible.
If you need help recognising the electrophilic center, use the button to highlight it (it's especially hard to see in the tert-butyl case, hint, hint).
Relative rate of
reaction with I-
Notice how as the steric crowding increases around the electrophilic center that the rate of reaction with iodide decreases.
The C-LG bond is broken during the rate determining step so the rate does depend on the nature of the leaving group. However, if a leaving group is too good, then an SN1 reaction may result.
Since the nucleophile is involved in the rate determining step, the nature of the nucleophile is very important in an SN2 reaction. The more reactive the nucleophile, the more likely the reaction will be SN2 rather than SN1.
When the nucleophile attacks in an SN2 it is on the opposite side to the position of the leaving group. As a result, the reaction will proceed with an inversion of configuration.
This pathway is most common for systems with poorer leaving groups, 1o or 2o substrates and stronger nucleophiles.
A typical example is the reaction of NaI with primary alkyl halides or tosylates.
|© Dr. Ian Hunt, Department of Chemistry|