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        Functional group is an alkene, therefore suffix = -eneThere are two alkenes, so insert the multiplier di
The longest continuous chain is C4 therefore root
plus "a" = buta
The C=C units are both at the ends so we can number
from either endLocants for C=C units are therefore 1- and 3-
 1,3-butadieneor
 buta-1,3-diene
 
 
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 CH2=CHH=CH2
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      | 
        Functional group is an alkene, therefore suffix = -eneThere are two alkenes, so insert the multiplier di
The longest continuous chain is C5 therefore root plus
"a" = penta
The first point of difference requires that we
number from the right as
drawnLocants for C=C units are therefore 1- and 3-The C3=C4 alkene has E stereochemistry
 (E)-1,3-pentadiene
 or(E)-penta-1,3-diene
 
 
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 CH3CH=CHH=CH2
 
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      | 
        Functional group is an alkene, therefore suffix = -eneThere are two alkenes, so insert the multiplier di
The longest continuous chain is C5 therefore root plus
"a" = pentaThe substituent is a C1 alkyl group i.e. a methyl groupThe first point of difference doesn't distinguish
the C=CSo, need to apply the first point of
difference to the alkyl substituent.
The first point of difference requires that we
number from the left as drawnThe methyl group locant is 2-Therefore the locants for C=C units are 1- and 4- 2-methyl-1,4-pentadiene
 or2-methylpenta-1,4-diene
 
 
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 CH3C(CH3)=CHH=CH2
 
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