Chem 351 Fall 2007 MT: Thermodynamics

Part 8: THERMODYNAMICS

a.
A = 2-methyl-2-butene (or 2-methylbut-2-ene and B = 2-methyl-1-butene (or 2-methylbut-1-ene)

b. CH2

c. A has a molecular formula = C5H10 so a MW = 70.13 g/mol. Therefore 0.5 moles = 35.65g.

d. (CH3)2CHCH=CH2

e. For C, the heat of formation = 5x(-93.9) + 5x(-68.4) - (-796) = -15.5 kcal/mol

f. Since A is the more stable product compared to B, A has a less exothermic heat of combustion than B. Therefore A = -792 kcal/mol (-3329 kJ/mol) and B = -794 kcal/mol (-3336 kJ/mol). Obviously C = -796kcal/mol (-3345 kJ/mol).

g. By comparing the structures of A, B and C we can see that if there are more alkyl groups on the bond it is more stable : A has 3, B has 2 and C has only 1.

h. (CH3)2CHCH2CH2OH

Common errors: